AP Calculus AB and BC
Limit of tan x as x Approaches pi/2 from the Left
The limit of tan x as x approaches pi over 2 from the left is infinity. Writing tangent as sine over cosine explains it: the numerator tends to 1 while the denominator shrinks to zero through positive values, so the quotient grows without bound.
Settled by one-sided analysis of sine over cosine.
Split the tangent
Approaching from the left, and . A fixed nonzero numerator over a vanishing denominator is unbounded, so the only question left is the sign.
Just left of the angle is still in the first quadrant, where cosine is POSITIVE. So the quotient is positive and grows without bound: the limit is .
Why the two sides disagree
From the right, is negative, so the same argument gives . The two one-sided limits differ, so the two-sided limit does not exist, and is a vertical asymptote of the tangent graph.
This is why an answer here MUST specify a side. Writing that the limit of at is infinity without saying from which side is not a partial answer, it is a wrong one.
Not sure which technique a limit wants?
The Limit Method Chooser walks the decision from direct substitution through factoring, the conjugate, and L'Hopital, and says why each one applies or fails.
Frequently asked questions
Is the limit of tan x at pi/2 infinity or does it not exist?
From the left it is and from the right it is , so the two-sided limit does not exist. Both facts are correct; they answer different questions.
Where are the other asymptotes of the tangent function?
At every odd multiple of , since those are exactly the zeros of cosine. The behaviour repeats with period .