AP Calculus AB and BC glossary

Curve Sketching

Also called: Graph sketching, Graphing with derivatives

Curve sketching is rebuilding the shape of a graph from the signs of its first and second derivatives.

Four shapes cover the local picture, one for each pairing of the two signs. With f>0f' > 0 and f>0f'' > 0 the curve rises and steepens. With f>0f' > 0 and f<0f'' < 0 it still rises, but with the slope decreasing, so the climb gets shallower without having to level off. With f<0f' < 0 and f>0f'' > 0 it falls with the slope increasing from below, so each step down is shallower than the last. With f<0f' < 0 and f<0f'' < 0 it falls ever more steeply. Direction comes from ff' and bend comes from ff''.

A sign chart keeps it organised. Mark every xx where ff' is zero or undefined on one number line and every xx where ff'' is zero or undefined on a second, test a point inside each interval, then read the shape off the pair of rows. Those rows describe the shape between the marked points and no more: f>0f' > 0 with f<0f'' < 0 fits lnx\ln x, x\sqrt{x} and 1ex1 - e^{-x} alike, three graphs that look nothing like each other, so intercepts, asymptotes and end behaviour limits are what pin the actual picture down. The chart is scratch work; the credit is in the sentence it lets you write, such as ff has a relative maximum at x=3x = 3 because ff is continuous at x=3x = 3 and ff' changes from positive to negative there. At a marked point where ff' is undefined, confirm that ff is continuous before applying that test.

The mistake

Calling every solution of f=0f'' = 0 an inflection point. Concavity changes only where ff'' changes sign. For f(x)=x4f(x) = x^4 the second derivative f(x)=12x2f''(x) = 12x^2 is zero at the origin and positive on both sides of it, so the graph is concave up the whole way across and has no inflection point at all.

Appears in: Unit 5: Analytical Applications