AP Calculus AB and BC

Derivative of ln 2x: Answer, Why the 2 Vanishes

The derivative of ln 2x with respect to x is 1 over x, exactly the same as the derivative of ln x. The chain rule contributes a factor of 2 which then cancels against the 2 in the denominator. The log rule explanation is that ln 2x equals ln 2 plus ln x, and the constant differentiates away.

ddx[ln2x]=1x\frac{d}{dx}\left[\ln 2x\right] = \frac{1}{x}

How to differentiate ln 2x

By the chain rule, the derivative of lnu\ln u is uu\frac{u'}{u}. With u=2xu = 2x the numerator is 22 and the denominator is 2x2x.

ddxln(2x)=22x=1x\frac{d}{dx}\ln(2x) = \frac{2}{2x} = \frac{1}{x}

The twos cancel, so the answer is identical to the derivative of lnx\ln x.

The log rule explanation

Splitting the logarithm first makes the result obvious without any cancellation.

ln2x=ln2+lnx\ln 2x = \ln 2 + \ln x

ln2\ln 2 is a constant, so it differentiates to zero and only 1x\frac{1}{x} survives. Geometrically, ln2x\ln 2x is lnx\ln x shifted vertically, and a vertical shift never changes slopes.

The same argument shows ddxln(kx)=1x\frac{d}{dx}\ln(kx) = \frac{1}{x} for ANY positive constant kk.

Where the derivative of ln 2x shows up on the AP exam

Topics 3.1 and 2.8 cover this on both exams. It is a favourite multiple choice item precisely because the obvious answer 2x\frac{2}{x} is wrong and looks right.

Contrast it with ln(x2)\ln\left(x^{2}\right), where the constant is an exponent rather than a factor: there the derivative IS 2x\frac{2}{x}.

Common mistakes with the derivative of ln 2x

  • Answering 2x\frac{2}{x}, keeping the chain rule factor but forgetting it cancels.
  • Answering 12x\frac{1}{2x}, forgetting the chain rule factor entirely.
  • Assuming the graphs are identical because the derivatives are. They differ by the constant ln2\ln 2, which is invisible to differentiation but not to the function.

Check yourself, not just the answer

Type derivatives and get graded on mathematical equivalence, with rule-level hints when you miss, in the Derivative Practice Checker.

Frequently asked questions

What is the derivative of ln 2x?

It is 1x\frac{1}{x}, the same as the derivative of lnx\ln x.

Why does the 2 disappear?

The chain rule puts a 22 on top and 2x2x underneath, and they cancel. Equivalently ln2x=ln2+lnx\ln 2x = \ln 2 + \ln x, and the constant has zero derivative.

What is the derivative of ln(kx)?

It is 1x\frac{1}{x} for every positive constant kk, by the same cancellation.

What is the derivative of ln(x^2)?

That one IS 2x\frac{2}{x}, because the constant is an exponent, so the log rule brings it out as a multiplier.