AP Calculus AB and BC

Derivative of e^2x: Answer, Chain Rule, Mistakes

The derivative of e to the 2x with respect to x is 2 times e to the 2x. The exponential differentiates to itself, and the chain rule multiplies by the derivative of the exponent, which is 2. In general e to the kx differentiates to k times e to the kx.

ddx[e2x]=2e2x\frac{d}{dx}\left[e^{2x}\right] = 2e^{2x}

How to differentiate e^(2x)

The outer function is the exponential, which is its own derivative, and the inner function is 2x2x.

ddxe2x=e2x2=2e2x\frac{d}{dx}e^{2x} = e^{2x}\cdot 2 = 2e^{2x}
ddxekx=kekx\frac{d}{dx}e^{kx} = ke^{kx}

Why this function solves a differential equation

The derivative is exactly 22 times the original function, so y=e2xy = e^{2x} satisfies dydx=2y\frac{dy}{dx} = 2y. That is the defining property of exponential growth, and it is why exponentials solve these equations.

A negative constant gives decay instead: ddxe2x=2e2x\frac{d}{dx}e^{-2x} = -2e^{-2x}, and the function falls toward zero.

Where the derivative of e^(2x) shows up on the AP exam

Topic 3.1 for the chain rule, and Unit 7 for growth and decay, on both exams. Reversed it gives e2xdx=e2x2+C\int e^{2x}\,dx = \frac{e^{2x}}{2} + C, where the same 22 divides rather than multiplies.

Common mistakes with the derivative of e^(2x)

  • Answering e2xe^{2x} and forgetting the chain rule factor.
  • Answering 2xe2x12xe^{2x-1}, applying the power rule to something that is not a power.
  • Confusing it with (ex)2\left(e^{x}\right)^{2}, which is the same function, and with ex2e^{x^{2}}, which is not: that one differentiates to 2xex22xe^{x^{2}}.

Check yourself, not just the answer

Type derivatives and get graded on mathematical equivalence, with rule-level hints when you miss, in the Derivative Practice Checker.

Frequently asked questions

What is the derivative of e^(2x)?

It is 2e2x2e^{2x}.

Why is there a factor of 2?

The chain rule multiplies by the derivative of the exponent 2x2x, which is 22.

What is the derivative of e^(kx)?

It is kekxke^{kx} for any constant kk.

What is the antiderivative of e^(2x)?

It is e2x2+C\frac{e^{2x}}{2} + C; the factor divides going backwards.